The heat required to raise the temperature of 7 kg of water from 10 oC to 80 oC and The specific heat of the water 4200 J/kg oC is
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The heat required to raise the temperature of 7 kg of water from 10°C to 80°C and The specific heat of the water 4.200 J/kg°C is 2.058.000 Joule.
Solution:
Known:
m = 7 kg
∆T = 80°C – 10°C = 70°C
c = 4.200 J/kg°C
Asked:
Q = ...?
Answer:
Q = m × c × ∆T
= 7 × 4.200 × 70
= 2.058.000 Joule or 2.058 kJ.
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